用SQL進行集合運算
發表時間:2023-07-10 來源:明輝站整理相關軟件相關文章人氣:
[摘要]這篇文章主要介紹了關于用SQL進行集合運算 ,有著一定的參考價值,現在分享給大家,有需要的朋友可以參考一下1、比較表和表drop table if exists tbl_a;create table...
這篇文章主要介紹了關于用SQL進行集合運算 ,有著一定的參考價值,現在分享給大家,有需要的朋友可以參考一下
1、比較表和表
drop table if exists tbl_a;create table tbl_a(
key1 varchar(10),
col_1 int4,
col_2 int4,
col_3 int4
);insert into tbl_a values('A', 2, 3, 4);
insert into tbl_a values('B', 0, 7, 9);
insert into tbl_a values('c', 5, 1, 6);
drop table if exists tbl_b;create table tbl_b(
key1 varchar(10),
col_1 int4,
col_2 int4,
col_3 int4
);
insert into tbl_b values('A', 2, 3, 4);
insert into tbl_b values('B', 0, 7, 9);
insert into tbl_b values('c', 5, 1, 6);-- ## 如果union a b 行數一致則兩張表相等 select count(1) row_cnt from ( select *
from tbl_A union
select * from tbl_b
) tmp
;
直接求兩表的不同之處
(select * from tbl_a except
select * from tbl_b) union all
(select * from tbl_b except
select * from tbl_a);
2、用差集實現關系除法運算
建表
drop table if exists skills;create table skills(
skill varchar(10)
);insert into skills values('oracle');
insert into skills values('unix');insert into skills values('java');drop table if exists empskills;create table empskills(
emp varchar(10),
skill varchar(10)
);insert into empskills values('相田','oracle');
insert into empskills values('相田','unix');
insert into empskills values('相田','java');
insert into empskills values('相田','c#');
insert into empskills values('神奇','oracle');
insert into empskills values('神奇','unix');
insert into empskills values('神奇','java');
insert into empskills values('平井','oracle');
insert into empskills values('平井','unix');
insert into empskills values('平井','PHP');
insert into empskills values('平井','Perl');
insert into empskills values('平井','C++');
insert into empskills values('若田部','Perl');
insert into empskills values('度來','oracle');
--把除法變成減法select distinct emp from empskills es1 where not exists
(select skill from skills
expect select skill from empskills es2 where es1.emp = es2.emp);
3、尋求相等的子集
drop table if exists supparts;create table supparts(
sup varchar(10),
part varchar(10)
);insert into supparts values('A', '螺絲');
insert into supparts values('A', '螺母');
insert into supparts values('A', '管子');
insert into supparts values('B', '螺絲');
insert into supparts values('B', '管子');
insert into supparts values('C', '螺絲');
insert into supparts values('C', '螺母');
insert into supparts values('C', '管子');
insert into supparts values('D', '螺絲');
insert into supparts values('D', '管子');
insert into supparts values('E','保險絲');
insert into supparts values('E', '螺母');
insert into supparts values('E', '管子');
insert into supparts values('F','保險絲');
思路:
兩個供應商都經營同種類型的零件 (簡單的按照零件列進行連接)
兩個供應商的零件類型數相同(即存在一一映射)(count限定)
select a.sup s1, b.sup s2 from supparts a, supparts b where a.sup < b.sup -- 生成供應商的全部組合
and a.part = b.part -- 條件1:經營同種類型的零件
group by a.sup, b.suphaving count(*) = (select count(1) -- 條件2:經營的零件的數量種類相同 a = 中間數 from supparts c where c.sup = a.sup) and count(*) = (select count(1) -- 條件2:經營的零件的數量種類相同 b = 中間數 from supparts d where d.sup = b.sup)
;
4、刪除重行
drop table if exists products;create table products(
rowid int4,
name1 varchar(10),
price int4
);insert into products values(1,'蘋果',50);insert into products values(2,'橘子',100);
insert into products values(3,'橘子',100);insert into products values(4,'橘子',100);
insert into products values(5,'香蕉',80);-- 刪除重行高效SQL語句(1):通過EXCEPT求補集delete from productswhere rowid in (select rowid -- 全部rowid from products
except -- 減去 select max(rowid) -- 要留下的rowid from products group by name1, price
);-- 刪除重行高效SQL語句(2):通過not indelete from products where rowid not in (select max(rowid) from products group by name1, price
);
練習
-- 改進中用union的比較select
case when count(1) = (select count(1) from tbl_A)
and count(1) = (select count(1)+1 from tbl_b)
then count(1) else '不相等' end row_cnt from ( select * from tbl_A union
select * from tbl_b
) tmp
;
內容多來自 《SQL進階教材》,僅做筆記。練習部分代碼均為原創。
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